Problem Summary
Given a binary tree, determine if it is a binary search tree.
Solution
I have wrote about this problem before: https://suzyz.github.io/2017/10/14/validate-binary-search-tree/
Now I would like to implement Solution 2 in that post. That is, carry out an inorder traversal with the help of a stack.
It is relatively harder to code, but not much work actually.
Code
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| * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: bool isValidBST(TreeNode* root) { stack<TreeNode *> st; TreeNode *pre = NULL; while (root != NULL || !st.empty()) { while (root != NULL) { st.push(root); root = root->left; } TreeNode *cur = st.top(); st.pop(); if (pre != NULL && cur->val <= pre->val) return false; pre = cur; root = cur->right; } return true; } };
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